101110001113 has 4 divisors (see below), whose sum is σ = 110301819408. Its totient is φ = 91918182820.

The previous prime is 101110001087. The next prime is 101110001117. The reversal of 101110001113 is 311100011101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101110001113 is a prime.

It is a super-2 number, since 2×101110001113² (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 101110001113.

It is not an unprimeable number, because it can be changed into a prime (101110001117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4595909131 + ... + 4595909152.

It is an arithmetic number, because the mean of its divisors is an integer number (27575454852).

Almost surely, 2^101110001113 is an apocalyptic number.

It is an amenable number.

101110001113 is a deficient number, since it is larger than the sum of its proper divisors (9191818295).

101110001113 is an equidigital number, since it uses as much as digits as its factorization.

101110001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9191818294.

The product of its (nonzero) digits is 3, while the sum is 10.

Adding to 101110001113 its reverse (311100011101), we get a palindrome (412210012214).

The spelling of 101110001113 in words is "one hundred one billion, one hundred ten million, one thousand, one hundred thirteen".