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101110113114 = 2316851685519
BaseRepresentation
bin101111000101010100…
…0011110001101011010
3100122222112111221011020
41132022220132031122
53124033142104424
6114241020343310
710206413531613
oct1361250361532
9318875457136
10101110113114
113997602855a
12177196a4b36
1396c47c15ca
144c72672c0a
15296b91c079
hex178aa1e35a

101110113114 has 8 divisors (see below), whose sum is σ = 202220226240. Its totient is φ = 33703371036.

The previous prime is 101110113103. The next prime is 101110113163. The reversal of 101110113114 is 411311011101.

It is a sphenic number, since it is the product of 3 distinct primes.

101110113114 is an admirable number.

It is a junction number, because it is equal to n+sod(n) for n = 101110113093 and 101110113102.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8425842754 + ... + 8425842765.

It is an arithmetic number, because the mean of its divisors is an integer number (25277528280).

Almost surely, 2101110113114 is an apocalyptic number.

101110113114 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

101110113114 is a wasteful number, since it uses less digits than its factorization.

101110113114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16851685524.

The product of its (nonzero) digits is 12, while the sum is 15.

Adding to 101110113114 its reverse (411311011101), we get a palindrome (512421124215).

The spelling of 101110113114 in words is "one hundred one billion, one hundred ten million, one hundred thirteen thousand, one hundred fourteen".

Divisors: 1 2 3 6 16851685519 33703371038 50555056557 101110113114