1011104013 has 4 divisors (see below), whose sum is σ = 1348138688. Its totient is φ = 674069340.

The previous prime is 1011104011. The next prime is 1011104027. The reversal of 1011104013 is 3104011101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3104011101 = 3 ⋅1034670367.

It is not a de Polignac number, because 1011104013 - 2¹ = 1011104011 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1011104013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011104011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 168517333 + ... + 168517338.

It is an arithmetic number, because the mean of its divisors is an integer number (337034672).

Almost surely, 2^1011104013 is an apocalyptic number.

It is an amenable number.

1011104013 is a deficient number, since it is larger than the sum of its proper divisors (337034675).

1011104013 is an equidigital number, since it uses as much as digits as its factorization.

1011104013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 337034674.

The product of its (nonzero) digits is 12, while the sum is 12.

The square root of 1011104013 is about 31797.8617677353. The cubic root of 1011104013 is about 1003.6877216588.

Adding to 1011104013 its reverse (3104011101), we get a palindrome (4115115114).

The spelling of 1011104013 in words is "one billion, eleven million, one hundred four thousand, thirteen".