Base | Representation |
---|---|
bin | 10110111111010111000011… |
… | …110011001110010010010001 |
3 | 111021000010110002222212012211 |
4 | 112333113003303032102101 |
5 | 101223101023141200423 |
6 | 555013445220152121 |
7 | 30204015365152231 |
oct | 2677270363162221 |
9 | 437003402885184 |
10 | 101111110100113 |
11 | 2a242a87765893 |
12 | b410016238641 |
13 | 44559768b7649 |
14 | 1ad7b37a49cc1 |
15 | ba51ea80c10d |
hex | 5bf5c3cce491 |
101111110100113 has 4 divisors (see below), whose sum is σ = 101780720100928. Its totient is φ = 100441500099300.
The previous prime is 101111110100069. The next prime is 101111110100173. The reversal of 101111110100113 is 311001011111101.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101111110100113 is a prime.
It is a super-3 number, since 3×1011111101001133 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 101111110100093 and 101111110100102.
It is not an unprimeable number, because it can be changed into a prime (101111110100173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 334805000181 + ... + 334805000482.
It is an arithmetic number, because the mean of its divisors is an integer number (25445180025232).
Almost surely, 2101111110100113 is an apocalyptic number.
It is an amenable number.
101111110100113 is a deficient number, since it is larger than the sum of its proper divisors (669610000815).
101111110100113 is an equidigital number, since it uses as much as digits as its factorization.
101111110100113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 669610000814.
The product of its (nonzero) digits is 3, while the sum is 13.
Adding to 101111110100113 its reverse (311001011111101), we get a palindrome (412112121211214).
The spelling of 101111110100113 in words is "one hundred one trillion, one hundred eleven billion, one hundred ten million, one hundred thousand, one hundred thirteen".
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