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101112110000003 = 593170509460371
BaseRepresentation
bin10110111111010111111111…
…011001100010011110000011
3111021000020000210111001000002
4112333113333121202132003
5101223110100130000003
6555014132335350215
730204052226155244
oct2677277731423603
9437006023431002
10101112110000003
112a243450120433
12b41025508236b
134455aa5abb09b
141ad7bd076cccb
15ba52584bda88
hex5bf5ff662783

101112110000003 has 4 divisors (see below), whose sum is σ = 101282619460968. Its totient is φ = 100941600539040.

The previous prime is 101112109999951. The next prime is 101112110000093. The reversal of 101112110000003 is 300000011211101.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101112110000003 - 234 = 101094930130819 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101112110000093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85254729593 + ... + 85254730778.

It is an arithmetic number, because the mean of its divisors is an integer number (25320654865242).

Almost surely, 2101112110000003 is an apocalyptic number.

101112110000003 is a deficient number, since it is larger than the sum of its proper divisors (170509460965).

101112110000003 is an equidigital number, since it uses as much as digits as its factorization.

101112110000003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 170509460964.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 101112110000003 its reverse (300000011211101), we get a palindrome (401112121211104).

The spelling of 101112110000003 in words is "one hundred one trillion, one hundred twelve billion, one hundred ten million, three", and thus it is an aban number.

Divisors: 1 593 170509460371 101112110000003