Base | Representation |
---|---|
bin | 10110111111010111111111… |
… | …011001100010011110000011 |
3 | 111021000020000210111001000002 |
4 | 112333113333121202132003 |
5 | 101223110100130000003 |
6 | 555014132335350215 |
7 | 30204052226155244 |
oct | 2677277731423603 |
9 | 437006023431002 |
10 | 101112110000003 |
11 | 2a243450120433 |
12 | b41025508236b |
13 | 4455aa5abb09b |
14 | 1ad7bd076cccb |
15 | ba52584bda88 |
hex | 5bf5ff662783 |
101112110000003 has 4 divisors (see below), whose sum is σ = 101282619460968. Its totient is φ = 100941600539040.
The previous prime is 101112109999951. The next prime is 101112110000093. The reversal of 101112110000003 is 300000011211101.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 101112110000003 - 234 = 101094930130819 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (101112110000093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85254729593 + ... + 85254730778.
It is an arithmetic number, because the mean of its divisors is an integer number (25320654865242).
Almost surely, 2101112110000003 is an apocalyptic number.
101112110000003 is a deficient number, since it is larger than the sum of its proper divisors (170509460965).
101112110000003 is an equidigital number, since it uses as much as digits as its factorization.
101112110000003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 170509460964.
The product of its (nonzero) digits is 6, while the sum is 11.
Adding to 101112110000003 its reverse (300000011211101), we get a palindrome (401112121211104).
The spelling of 101112110000003 in words is "one hundred one trillion, one hundred twelve billion, one hundred ten million, three", and thus it is an aban number.
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