10111214113 has 24 divisors (see below), whose sum is σ = 13678758464. Its totient is φ = 7272793440.

The previous prime is 10111214111. The next prime is 10111214147. The reversal of 10111214113 is 31141211101.

It is not a de Polignac number, because 10111214113 - 2¹ = 10111214111 is a prime.

It is a super-3 number, since 3×10111214113³ (a number of 31 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (10111214111) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 448131 + ... + 470152.

Almost surely, 2^10111214113 is an apocalyptic number.

10111214113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

10111214113 is a deficient number, since it is larger than the sum of its proper divisors (3567544351).

10111214113 is a wasteful number, since it uses less digits than its factorization.

10111214113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 918325 (or 918314 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 16.

Adding to 10111214113 its reverse (31141211101), we get a palindrome (41252425214).

The spelling of 10111214113 in words is "ten billion, one hundred eleven million, two hundred fourteen thousand, one hundred thirteen".