101112201101021 has 4 divisors (see below), whose sum is σ = 110304219382944. Its totient is φ = 91920182819100.

The previous prime is 101112201100997. The next prime is 101112201101111. The reversal of 101112201101021 is 120101102211101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101112201101021 - 2¹⁰ = 101112201099997 is a prime.

It is a super-2 number, since 2×101112201101021² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101112201100987 and 101112201101005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101112201103021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4596009140945 + ... + 4596009140966.

It is an arithmetic number, because the mean of its divisors is an integer number (27576054845736).

Almost surely, 2^{101112201101021} is an apocalyptic number.

101112201101021 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

101112201101021 is a deficient number, since it is larger than the sum of its proper divisors (9192018281923).

101112201101021 is an equidigital number, since it uses as much as digits as its factorization.

101112201101021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9192018281922.

The product of its (nonzero) digits is 8, while the sum is 14.

Adding to 101112201101021 its reverse (120101102211101), we get a palindrome (221213303312122).

The spelling of 101112201101021 in words is "one hundred one trillion, one hundred twelve billion, two hundred one million, one hundred one thousand, twenty-one".