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10111220131 = 55211831411
BaseRepresentation
bin10010110101010110…
…01111100110100011
3222002200001012110111
421122223033212203
5131201433021011
64351154312151
7505364644615
oct113253174643
928080035414
1010111220131
11431957a381
121b62288657
13c51a5bcbc
146bcc34db5
153e2a2c121
hex25aacf9a3

10111220131 has 4 divisors (see below), whose sum is σ = 10113057064. Its totient is φ = 10109383200.

The previous prime is 10111220117. The next prime is 10111220137. The reversal of 10111220131 is 13102211101.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10111220131 - 223 = 10102831523 is a prime.

It is a super-2 number, since 2×101112201312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10111220137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 910185 + ... + 921226.

It is an arithmetic number, because the mean of its divisors is an integer number (2528264266).

Almost surely, 210111220131 is an apocalyptic number.

10111220131 is a deficient number, since it is larger than the sum of its proper divisors (1836933).

10111220131 is an equidigital number, since it uses as much as digits as its factorization.

10111220131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1836932.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 10111220131 its reverse (13102211101), we get a palindrome (23213431232).

The spelling of 10111220131 in words is "ten billion, one hundred eleven million, two hundred twenty thousand, one hundred thirty-one".

Divisors: 1 5521 1831411 10111220131