Base | Representation |
---|---|
bin | 10110111111011000000110… |
… | …000101001111100010110001 |
3 | 111021000020022121110022212202 |
4 | 112333120012011033202301 |
5 | 101223110312330320423 |
6 | 555014151422432545 |
7 | 30204055060160111 |
oct | 2677300605174261 |
9 | 437006277408782 |
10 | 101112222120113 |
11 | 2a2434a843a986 |
12 | b410286732755 |
13 | 4455ac30b6449 |
14 | 1ad7c015d7041 |
15 | ba5263269728 |
hex | 5bf60614f8b1 |
101112222120113 has 8 divisors (see below), whose sum is σ = 101146562298432. Its totient is φ = 101077886302096.
The previous prime is 101112222120071. The next prime is 101112222120127. The reversal of 101112222120113 is 311021222211101.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 101112222120113 - 214 = 101112222103729 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (101112222120313) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45635906 + ... + 47800212.
It is an arithmetic number, because the mean of its divisors is an integer number (12643320287304).
Almost surely, 2101112222120113 is an apocalyptic number.
It is an amenable number.
101112222120113 is a deficient number, since it is larger than the sum of its proper divisors (34340178319).
101112222120113 is a wasteful number, since it uses less digits than its factorization.
101112222120113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2180151.
The product of its (nonzero) digits is 96, while the sum is 20.
Adding to 101112222120113 its reverse (311021222211101), we get a palindrome (412133444331214).
The spelling of 101112222120113 in words is "one hundred one trillion, one hundred twelve billion, two hundred twenty-two million, one hundred twenty thousand, one hundred thirteen".
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