10111224040131 has 16 divisors (see below), whose sum is σ = 13813161667200. Its totient is φ = 6575115727680.

The previous prime is 10111224040111. The next prime is 10111224040139. The reversal of 10111224040131 is 13104042211101.

10111224040131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 10111224040131 - 2⁷ = 10111224040003 is a prime.

It is a super-2 number, since 2×10111224040131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10111224040098 and 10111224040107.

It is not an unprimeable number, because it can be changed into a prime (10111224040139) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7433725 + ... + 8688078.

It is an arithmetic number, because the mean of its divisors is an integer number (863322604200).

Almost surely, 2^{10111224040131} is an apocalyptic number.

10111224040131 is a deficient number, since it is larger than the sum of its proper divisors (3701937627069).

10111224040131 is a wasteful number, since it uses less digits than its factorization.

10111224040131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16126946.

The product of its (nonzero) digits is 192, while the sum is 21.

Adding to 10111224040131 its reverse (13104042211101), we get a palindrome (23215266251232).

The spelling of 10111224040131 in words is "ten trillion, one hundred eleven billion, two hundred twenty-four million, forty thousand, one hundred thirty-one".