10111310303301 has 12 divisors (see below), whose sum is σ = 14749832192940. Its totient is φ = 6674132212800.

The previous prime is 10111310303287. The next prime is 10111310303309. The reversal of 10111310303301 is 10330301311101.

10111310303301 is a `hidden beast` number, since 10 + 1 + 11 + 310 + 3 + 0 + 330 + 1 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 6936107055201 + 3175203248100 = 2633649^2 + 1781910^2 .

It is not a de Polignac number, because 10111310303301 - 2⁷ = 10111310303173 is a prime.

It is a super-2 number, since 2×10111310303301² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10111310303309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5561775936 + ... + 5561777753.

It is an arithmetic number, because the mean of its divisors is an integer number (1229152682745).

Almost surely, 2^{10111310303301} is an apocalyptic number.

It is an amenable number.

10111310303301 is a deficient number, since it is larger than the sum of its proper divisors (4638521889639).

10111310303301 is a wasteful number, since it uses less digits than its factorization.

10111310303301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11123553796 (or 11123553793 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 18.

Adding to 10111310303301 its reverse (10330301311101), we get a palindrome (20441611614402).

The spelling of 10111310303301 in words is "ten trillion, one hundred eleven billion, three hundred ten million, three hundred three thousand, three hundred one".