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1011131113004 = 222447471032833
BaseRepresentation
bin11101011011011000001…
…11000101111000101100
310120122220110120112221122
432231230013011320230
5113031244031104004
62052301320520112
7133023525436355
oct16555407057054
93518813515848
101011131113004
1135a900175941
12143b69920038
137447040b43c
1436d208c6d2c
151b47daa3cbe
hexeb6c1c5e2c

1011131113004 has 12 divisors (see below), whose sum is σ = 1769488390824. Its totient is φ = 505563001344.

The previous prime is 1011131112991. The next prime is 1011131113009. The reversal of 1011131113004 is 4003111311101.

It is a super-2 number, since 2×10111311130042 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1011131113009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 462572 + ... + 1495404.

It is an arithmetic number, because the mean of its divisors is an integer number (147457365902).

Almost surely, 21011131113004 is an apocalyptic number.

It is an amenable number.

1011131113004 is a deficient number, since it is larger than the sum of its proper divisors (758357277820).

1011131113004 is a wasteful number, since it uses less digits than its factorization.

1011131113004 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1277584 (or 1277582 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1011131113004 its reverse (4003111311101), we get a palindrome (5014242424105).

The spelling of 1011131113004 in words is "one trillion, eleven billion, one hundred thirty-one million, one hundred thirteen thousand, four".

Divisors: 1 2 4 244747 489494 978988 1032833 2065666 4131332 252782778251 505565556502 1011131113004