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10111312993 = 47215134319
BaseRepresentation
bin10010110101010111…
…00110010001100001
3222002200012220211211
421122223212101201
5131201444003433
64351200310121
7505365512425
oct113253462141
928080186754
1010111312993
114319633121
121b62312341
13c51a92352
146bcc5ab85
153e2a498cd
hex25aae6461

10111312993 has 4 divisors (see below), whose sum is σ = 10326447360. Its totient is φ = 9896178628.

The previous prime is 10111312979. The next prime is 10111313021. The reversal of 10111312993 is 39921311101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10111312993 - 229 = 9574442081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10111312963) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107567113 + ... + 107567206.

It is an arithmetic number, because the mean of its divisors is an integer number (2581611840).

Almost surely, 210111312993 is an apocalyptic number.

It is an amenable number.

10111312993 is a deficient number, since it is larger than the sum of its proper divisors (215134367).

10111312993 is an equidigital number, since it uses as much as digits as its factorization.

10111312993 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 215134366.

The product of its (nonzero) digits is 1458, while the sum is 31.

The spelling of 10111312993 in words is "ten billion, one hundred eleven million, three hundred twelve thousand, nine hundred ninety-three".

Divisors: 1 47 215134319 10111312993