10111324013 has 4 divisors (see below), whose sum is σ = 11555798880. Its totient is φ = 8666849148.

The previous prime is 10111324001. The next prime is 10111324021. The reversal of 10111324013 is 31042311101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31042311101 = 1297 ⋅23933933.

It is a cyclic number.

It is not a de Polignac number, because 10111324013 - 2¹² = 10111319917 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10111323982 and 10111324000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10111324043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 722237423 + ... + 722237436.

It is an arithmetic number, because the mean of its divisors is an integer number (2888949720).

Almost surely, 2^10111324013 is an apocalyptic number.

It is an amenable number.

10111324013 is a deficient number, since it is larger than the sum of its proper divisors (1444474867).

10111324013 is an equidigital number, since it uses as much as digits as its factorization.

10111324013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1444474866.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 10111324013 its reverse (31042311101), we get a palindrome (41153635114).

The spelling of 10111324013 in words is "ten billion, one hundred eleven million, three hundred twenty-four thousand, thirteen".