10111331135131 has 8 divisors (see below), whose sum is σ = 10448960329728. Its totient is φ = 9774418017000.

The previous prime is 10111331135099. The next prime is 10111331135183. The reversal of 10111331135131 is 13153113311101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10111331135131 - 2⁵ = 10111331135099 is a prime.

It is a super-2 number, since 2×10111331135131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10111331135096 and 10111331135105.

It is not an unprimeable number, because it can be changed into a prime (10111331135431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 178990405 + ... + 179046886.

It is an arithmetic number, because the mean of its divisors is an integer number (1306120041216).

Almost surely, 2^{10111331135131} is an apocalyptic number.

10111331135131 is a deficient number, since it is larger than the sum of its proper divisors (337629194597).

10111331135131 is an equidigital number, since it uses as much as digits as its factorization.

10111331135131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 358038233.

The product of its (nonzero) digits is 405, while the sum is 25.

Adding to 10111331135131 its reverse (13153113311101), we get a palindrome (23264444446232).

The spelling of 10111331135131 in words is "ten trillion, one hundred eleven billion, three hundred thirty-one million, one hundred thirty-five thousand, one hundred thirty-one".