Base | Representation |
---|---|
bin | 10110111111011001001000… |
… | …000111110110011101111111 |
3 | 111021000100011211022112200101 |
4 | 112333121020013312131333 |
5 | 101223120100001200340 |
6 | 555014453402341531 |
7 | 30204124402640335 |
oct | 2677311007663577 |
9 | 437010154275611 |
10 | 101113330100095 |
11 | 2a243a16905715 |
12 | b4105357ba8a7 |
13 | 4455c3b7cc3c1 |
14 | 1ad7ca8811b55 |
15 | ba52ca679c9a |
hex | 5bf6481f677f |
101113330100095 has 8 divisors (see below), whose sum is σ = 121337735848560. Its totient is φ = 80889504261120.
The previous prime is 101113330100021. The next prime is 101113330100117. The reversal of 101113330100095 is 590001033311101.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 101113330100095 - 213 = 101113330091903 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 144593685 + ... + 145291294.
It is an arithmetic number, because the mean of its divisors is an integer number (15167216981070).
Almost surely, 2101113330100095 is an apocalyptic number.
101113330100095 is a deficient number, since it is larger than the sum of its proper divisors (20224405748465).
101113330100095 is an equidigital number, since it uses as much as digits as its factorization.
101113330100095 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 289954745.
The product of its (nonzero) digits is 1215, while the sum is 28.
Adding to 101113330100095 its reverse (590001033311101), we get a palindrome (691114363411196).
The spelling of 101113330100095 in words is "one hundred one trillion, one hundred thirteen billion, three hundred thirty million, one hundred thousand, ninety-five".
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