101113442432234 has 4 divisors (see below), whose sum is σ = 151670163648354. Its totient is φ = 50556721216116.

The previous prime is 101113442432231. The next prime is 101113442432257. The reversal of 101113442432234 is 432234244311101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 80696175441025 + 20417266991209 = 8983105^2 + 4518547^2 .

It is a junction number, because it is equal to n+sod(n) for n = 101113442432194 and 101113442432203.

It is not an unprimeable number, because it can be changed into a prime (101113442432231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25278360608057 + ... + 25278360608060.

Almost surely, 2^{101113442432234} is an apocalyptic number.

101113442432234 is a deficient number, since it is larger than the sum of its proper divisors (50556721216120).

101113442432234 is an equidigital number, since it uses as much as digits as its factorization.

101113442432234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50556721216119.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 101113442432234 its reverse (432234244311101), we get a palindrome (533347686743335).

The spelling of 101113442432234 in words is "one hundred one trillion, one hundred thirteen billion, four hundred forty-two million, four hundred thirty-two thousand, two hundred thirty-four".