101114100341031 has 4 divisors (see below), whose sum is σ = 134818800454712. Its totient is φ = 67409400227352.

The previous prime is 101114100341011. The next prime is 101114100341123. The reversal of 101114100341031 is 130143001411101.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 101114100341031 - 2⁵ = 101114100340999 is a prime.

It is a super-2 number, since 2×101114100341031² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101114100340989 and 101114100341007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101114100341011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16852350056836 + ... + 16852350056841.

It is an arithmetic number, because the mean of its divisors is an integer number (33704700113678).

Almost surely, 2^{101114100341031} is an apocalyptic number.

101114100341031 is a deficient number, since it is larger than the sum of its proper divisors (33704700113681).

101114100341031 is an equidigital number, since it uses as much as digits as its factorization.

101114100341031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33704700113680.

The product of its (nonzero) digits is 144, while the sum is 21.

Adding to 101114100341031 its reverse (130143001411101), we get a palindrome (231257101752132).

The spelling of 101114100341031 in words is "one hundred one trillion, one hundred fourteen billion, one hundred million, three hundred forty-one thousand, thirty-one".