1011200202133 has 4 divisors (see below), whose sum is σ = 1103127493248. Its totient is φ = 919272911020.

The previous prime is 1011200202121. The next prime is 1011200202137. The reversal of 1011200202133 is 3312020021101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011200202133 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011200202137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45963645541 + ... + 45963645562.

It is an arithmetic number, because the mean of its divisors is an integer number (275781873312).

Almost surely, 2^{1011200202133} is an apocalyptic number.

It is an amenable number.

1011200202133 is a deficient number, since it is larger than the sum of its proper divisors (91927291115).

1011200202133 is an equidigital number, since it uses as much as digits as its factorization.

1011200202133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91927291114.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1011200202133 its reverse (3312020021101), we get a palindrome (4323220223234).

The spelling of 1011200202133 in words is "one trillion, eleven billion, two hundred million, two hundred two thousand, one hundred thirty-three".