Base | Representation |
---|---|
bin | 10010110101011100… |
… | …10000110001000011 |
3 | 222002201112101210012 |
4 | 21122232100301003 |
5 | 131202133330311 |
6 | 4351223255135 |
7 | 505404451412 |
oct | 113256206103 |
9 | 28081471705 |
10 | 10112011331 |
11 | 4319a6a864 |
12 | 1b625aa4ab |
13 | c51c78176 |
14 | 6bcd9d479 |
15 | 3e2b3678b |
hex | 25ab90c43 |
10112011331 has 4 divisors (see below), whose sum is σ = 10112269752. Its totient is φ = 10111752912.
The previous prime is 10112011309. The next prime is 10112011361. The reversal of 10112011331 is 13311021101.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13311021101 = 7 ⋅1901574443.
It is a cyclic number.
It is not a de Polignac number, because 10112011331 - 214 = 10111994947 is a prime.
It is a super-3 number, since 3×101120113313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10112011361) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 57101 + ... + 153246.
It is an arithmetic number, because the mean of its divisors is an integer number (2528067438).
Almost surely, 210112011331 is an apocalyptic number.
10112011331 is a deficient number, since it is larger than the sum of its proper divisors (258421).
10112011331 is an equidigital number, since it uses as much as digits as its factorization.
10112011331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 258420.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 10112011331 its reverse (13311021101), we get a palindrome (23423032432).
The spelling of 10112011331 in words is "ten billion, one hundred twelve million, eleven thousand, three hundred thirty-one".
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