10112023134031 has 16 divisors (see below), whose sum is σ = 12568790380608. Its totient is φ = 7921506528000.

The previous prime is 10112023134019. The next prime is 10112023134133. The reversal of 10112023134031 is 13043132021101.

It is not a de Polignac number, because 10112023134031 - 2²¹ = 10112021036879 is a prime.

It is a super-2 number, since 2×10112023134031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10112023133993 and 10112023134011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10112023134431) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 550095430 + ... + 550113811.

It is an arithmetic number, because the mean of its divisors is an integer number (785549398788).

Almost surely, 2^{10112023134031} is an apocalyptic number.

10112023134031 is a deficient number, since it is larger than the sum of its proper divisors (2456767246577).

10112023134031 is a wasteful number, since it uses less digits than its factorization.

10112023134031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1100209362.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 10112023134031 its reverse (13043132021101), we get a palindrome (23155155155132).

The spelling of 10112023134031 in words is "ten trillion, one hundred twelve billion, twenty-three million, one hundred thirty-four thousand, thirty-one".