Base | Representation |
---|---|
bin | 10110111111100000010001… |
… | …010110011110100100111111 |
3 | 111021001001222102200211121220 |
4 | 112333200101112132210333 |
5 | 101223231302241401421 |
6 | 555022202511124423 |
7 | 30204515450360115 |
oct | 2677402126364477 |
9 | 437031872624556 |
10 | 101121001122111 |
11 | 2a2471a2a07033 |
12 | b411b16813713 |
13 | 4456891b39999 |
14 | 1ad83d5521ab5 |
15 | ba55c8d403c6 |
hex | 5bf81159e93f |
101121001122111 has 16 divisors (see below), whose sum is σ = 135027957254016. Its totient is φ = 67314044691936.
The previous prime is 101121001122091. The next prime is 101121001122121. The reversal of 101121001122111 is 111221100121101.
It is not a de Polignac number, because 101121001122111 - 27 = 101121001121983 is a prime.
It is a super-2 number, since 2×1011210011221112 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (101121001122121) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15842896 + ... + 21289418.
It is an arithmetic number, because the mean of its divisors is an integer number (8439247328376).
Almost surely, 2101121001122111 is an apocalyptic number.
101121001122111 is a deficient number, since it is larger than the sum of its proper divisors (33906956131905).
101121001122111 is an equidigital number, since it uses as much as digits as its factorization.
101121001122111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5455702.
The product of its (nonzero) digits is 8, while the sum is 15.
Adding to 101121001122111 its reverse (111221100121101), we get a palindrome (212342101243212).
The spelling of 101121001122111 in words is "one hundred one trillion, one hundred twenty-one billion, one million, one hundred twenty-two thousand, one hundred eleven".
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