10112110012111 has 4 divisors (see below), whose sum is σ = 10113654559672. Its totient is φ = 10110565464552.

The previous prime is 10112110012061. The next prime is 10112110012133. The reversal of 10112110012111 is 11121001121101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10112110012111 - 2¹¹ = 10112110010063 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10112110012091 and 10112110012100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10112110019111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 772263960 + ... + 772277053.

It is an arithmetic number, because the mean of its divisors is an integer number (2528413639918).

Almost surely, 2^{10112110012111} is an apocalyptic number.

10112110012111 is a deficient number, since it is larger than the sum of its proper divisors (1544547561).

10112110012111 is an equidigital number, since it uses as much as digits as its factorization.

10112110012111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1544547560.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 10112110012111 its reverse (11121001121101), we get a palindrome (21233111133212).

The spelling of 10112110012111 in words is "ten trillion, one hundred twelve billion, one hundred ten million, twelve thousand, one hundred eleven".