101122120012111 has 4 divisors (see below), whose sum is σ = 110315040013224. Its totient is φ = 91929200011000.

The previous prime is 101122120012093. The next prime is 101122120012127. The reversal of 101122120012111 is 111210021221101.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 101122120012111 - 2⁹ = 101122120011599 is a prime.

It is a super-3 number, since 3×101122120012111³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101122120012211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4596460000540 + ... + 4596460000561.

It is an arithmetic number, because the mean of its divisors is an integer number (27578760003306).

Almost surely, 2^{101122120012111} is an apocalyptic number.

101122120012111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

101122120012111 is a deficient number, since it is larger than the sum of its proper divisors (9192920001113).

101122120012111 is an equidigital number, since it uses as much as digits as its factorization.

101122120012111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9192920001112.

The product of its (nonzero) digits is 16, while the sum is 16.

Adding to 101122120012111 its reverse (111210021221101), we get a palindrome (212332141233212).

The spelling of 101122120012111 in words is "one hundred one trillion, one hundred twenty-two billion, one hundred twenty million, twelve thousand, one hundred eleven".