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101122133011 = 409247242379
BaseRepresentation
bin101111000101101011…
…0010100110000010011
3100200000101010121100121
41132023112110300103
53124044231224021
6114242130131111
710206620643214
oct1361326246023
9320011117317
10101122133011
1139981898259
1217721720a97
1396c713c683
144c740c140b
15296c9e3741
hex178b594c13

101122133011 has 4 divisors (see below), whose sum is σ = 101369375800. Its totient is φ = 100874890224.

The previous prime is 101122133009. The next prime is 101122133023. The reversal of 101122133011 is 110331221101.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101122133011 - 21 = 101122133009 is a prime.

It is a super-2 number, since 2×1011221330112 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101122143011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 123620781 + ... + 123621598.

It is an arithmetic number, because the mean of its divisors is an integer number (25342343950).

Almost surely, 2101122133011 is an apocalyptic number.

101122133011 is a deficient number, since it is larger than the sum of its proper divisors (247242789).

101122133011 is an equidigital number, since it uses as much as digits as its factorization.

101122133011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 247242788.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 101122133011 its reverse (110331221101), we get a palindrome (211453354112).

The spelling of 101122133011 in words is "one hundred one billion, one hundred twenty-two million, one hundred thirty-three thousand, eleven".

Divisors: 1 409 247242379 101122133011