Base | Representation |
---|---|
bin | 1001001100100110111111… |
… | …1101001000001100101010 |
3 | 1022210201102210020112021002 |
4 | 2103021233331020030222 |
5 | 2311134322203410442 |
6 | 33301254523315002 |
7 | 2062404342630134 |
oct | 223115775101452 |
9 | 38721383215232 |
10 | 10112231310122 |
11 | 3249633a49487 |
12 | 117399997ba62 |
13 | 58476b9ca176 |
14 | 26d6127c0054 |
15 | 128097d8e732 |
hex | 9326ff4832a |
10112231310122 has 4 divisors (see below), whose sum is σ = 15168346965186. Its totient is φ = 5056115655060.
The previous prime is 10112231310119. The next prime is 10112231310149. The reversal of 10112231310122 is 22101313221101.
10112231310122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 5565489638641 + 4546741671481 = 2359129^2 + 2132309^2 .
It is a junction number, because it is equal to n+sod(n) for n = 10112231310094 and 10112231310103.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2528057827529 + ... + 2528057827532.
Almost surely, 210112231310122 is an apocalyptic number.
10112231310122 is a deficient number, since it is larger than the sum of its proper divisors (5056115655064).
10112231310122 is an equidigital number, since it uses as much as digits as its factorization.
10112231310122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5056115655063.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 10112231310122 its reverse (22101313221101), we get a palindrome (32213544531223).
The spelling of 10112231310122 in words is "ten trillion, one hundred twelve billion, two hundred thirty-one million, three hundred ten thousand, one hundred twenty-two".
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