Search a number
-
+
10112310013 = 13777870001
BaseRepresentation
bin10010110101011110…
…11001101011111101
3222002202002120111111
421122233121223331
5131202222410023
64351233522021
7505410134251
oct113257315375
928082076444
1010112310013
11431a154203
121b62713311
13c520510c0
146bd03a261
153e2b9500d
hex25abd9afd

10112310013 has 4 divisors (see below), whose sum is σ = 10890180028. Its totient is φ = 9334440000.

The previous prime is 10112309989. The next prime is 10112310023. The reversal of 10112310013 is 31001321101.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3404372409 + 6707937604 = 58347^2 + 81902^2 .

It is a cyclic number.

It is not a de Polignac number, because 10112310013 - 217 = 10112178941 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (13), and also a Moran number because the ratio is a prime number: 777870001 = 10112310013 / (1 + 0 + 1 + 1 + 2 + 3 + 1 + 0 + 0 + 1 + 3).

It is a junction number, because it is equal to n+sod(n) for n = 10112309975 and 10112310002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10112310023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 388934988 + ... + 388935013.

It is an arithmetic number, because the mean of its divisors is an integer number (2722545007).

Almost surely, 210112310013 is an apocalyptic number.

10112310013 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

10112310013 is a deficient number, since it is larger than the sum of its proper divisors (777870015).

10112310013 is an equidigital number, since it uses as much as digits as its factorization.

10112310013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 777870014.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 10112310013 its reverse (31001321101), we get a palindrome (41113631114).

The spelling of 10112310013 in words is "ten billion, one hundred twelve million, three hundred ten thousand, thirteen".

Divisors: 1 13 777870001 10112310013