1011231234434 has 8 divisors (see below), whose sum is σ = 1516876991868. Its totient is φ = 505605570480.

The previous prime is 1011231234371. The next prime is 1011231234439. The reversal of 1011231234434 is 4344321321101.

It can be written as a sum of positive squares in 2 ways, for example, as 995399303809 + 15831930625 = 997697^2 + 125825^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1011231234434² (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1011231234397 and 1011231234406.

It is not an unprimeable number, because it can be changed into a prime (1011231234439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4896917 + ... + 5099240.

Almost surely, 2^{1011231234434} is an apocalyptic number.

1011231234434 is a deficient number, since it is larger than the sum of its proper divisors (505645757434).

1011231234434 is an equidigital number, since it uses as much as digits as its factorization.

1011231234434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10046740.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1011231234434 its reverse (4344321321101), we get a palindrome (5355552555535).

The spelling of 1011231234434 in words is "one trillion, eleven billion, two hundred thirty-one million, two hundred thirty-four thousand, four hundred thirty-four".