101123131413 has 4 divisors (see below), whose sum is σ = 134830841888. Its totient is φ = 67415420940.

The previous prime is 101123131393. The next prime is 101123131427. The reversal of 101123131413 is 314131321101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 101123131413 - 2¹⁸ = 101122869269 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 101123131413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101123135413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16853855233 + ... + 16853855238.

It is an arithmetic number, because the mean of its divisors is an integer number (33707710472).

Almost surely, 2^101123131413 is an apocalyptic number.

It is an amenable number.

101123131413 is a deficient number, since it is larger than the sum of its proper divisors (33707710475).

101123131413 is an equidigital number, since it uses as much as digits as its factorization.

101123131413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33707710474.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 101123131413 its reverse (314131321101), we get a palindrome (415254452514).

The spelling of 101123131413 in words is "one hundred one billion, one hundred twenty-three million, one hundred thirty-one thousand, four hundred thirteen".