Base | Representation |
---|---|
bin | 10110111111100010010110… |
… | …010001111011100110011111 |
3 | 111021001021201212011121112221 |
4 | 112333202112101323212133 |
5 | 101223300334203044444 |
6 | 555023212055410211 |
7 | 30204624640515346 |
oct | 2677422621734637 |
9 | 437037655147487 |
10 | 101123231299999 |
11 | 2a248137878757 |
12 | b412439683967 |
13 | 4456b58ba627c |
14 | 1ad85677b6b5d |
15 | ba56a9a1da84 |
hex | 5bf89647b99f |
101123231299999 has 4 divisors (see below), whose sum is σ = 101348450078400. Its totient is φ = 100898012521600.
The previous prime is 101123231299997. The next prime is 101123231300071. The reversal of 101123231299999 is 999992132321101.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 101123231299999 - 21 = 101123231299997 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (101123231299991) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 112609388527 + ... + 112609389424.
It is an arithmetic number, because the mean of its divisors is an integer number (25337112519600).
Almost surely, 2101123231299999 is an apocalyptic number.
101123231299999 is a deficient number, since it is larger than the sum of its proper divisors (225218778401).
101123231299999 is an equidigital number, since it uses as much as digits as its factorization.
101123231299999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 225218778400.
The product of its (nonzero) digits is 4251528, while the sum is 61.
The spelling of 101123231299999 in words is "one hundred one trillion, one hundred twenty-three billion, two hundred thirty-one million, two hundred ninety-nine thousand, nine hundred ninety-nine".
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