Base | Representation |
---|---|
bin | 11101011011100100100… |
… | …00110101101001110111 |
3 | 10120200011122210120202211 |
4 | 32231302100311221313 |
5 | 113032001442100010 |
6 | 2052315445114251 |
7 | 133026220664251 |
oct | 16556220655167 |
9 | 3520148716684 |
10 | 1011234331255 |
11 | 35a953465285 |
12 | 143b983b8987 |
13 | 7448890aa25 |
14 | 36d304b4cd1 |
15 | 1b487b9208a |
hex | eb72435a77 |
1011234331255 has 8 divisors (see below), whose sum is σ = 1215123260400. Its totient is φ = 807892756416.
The previous prime is 1011234331249. The next prime is 1011234331271. The reversal of 1011234331255 is 5521334321101.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1011234331255 - 235 = 976874592887 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 136834510 + ... + 136841899.
It is an arithmetic number, because the mean of its divisors is an integer number (151890407550).
Almost surely, 21011234331255 is an apocalyptic number.
1011234331255 is a deficient number, since it is larger than the sum of its proper divisors (203888929145).
1011234331255 is an equidigital number, since it uses as much as digits as its factorization.
1011234331255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 273677153.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 1011234331255 its reverse (5521334321101), we get a palindrome (6532568652356).
The spelling of 1011234331255 in words is "one trillion, eleven billion, two hundred thirty-four million, three hundred thirty-one thousand, two hundred fifty-five".
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