101125232333433 has 48 divisors (see below), whose sum is σ = 182181516656256. Its totient is φ = 52512815877120.

The previous prime is 101125232333431. The next prime is 101125232333507. The reversal of 101125232333433 is 334333232521101.

101125232333433 is a `hidden beast` number, since 1 + 0 + 1 + 1 + 252 + 32 + 33 + 343 + 3 = 666.

It is not a de Polignac number, because 101125232333433 - 2¹ = 101125232333431 is a prime.

It is a super-2 number, since 2×101125232333433² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (101125232333431) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 25618966 + ... + 29301567.

It is an arithmetic number, because the mean of its divisors is an integer number (3795448263672).

Almost surely, 2^{101125232333433} is an apocalyptic number.

It is an amenable number.

101125232333433 is a deficient number, since it is larger than the sum of its proper divisors (81056284322823).

101125232333433 is a wasteful number, since it uses less digits than its factorization.

101125232333433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54923214 (or 54923211 counting only the distinct ones).

The product of its (nonzero) digits is 116640, while the sum is 36.

Adding to 101125232333433 its reverse (334333232521101), we get a palindrome (435458464854534).

The spelling of 101125232333433 in words is "one hundred one trillion, one hundred twenty-five billion, two hundred thirty-two million, three hundred thirty-three thousand, four hundred thirty-three".