10113000315 has 48 divisors (see below), whose sum is σ = 18087148800. Its totient is φ = 4820115520.

The previous prime is 10113000281. The next prime is 10113000343. The reversal of 10113000315 is 51300031101.

10113000315 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 10113000315 - 2⁶ = 10113000251 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a junction number, because it is equal to n+sod(n) for n = 10113000294 and 10113000303.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 59866 + ... + 154304.

It is an arithmetic number, because the mean of its divisors is an integer number (376815600).

Almost surely, 2^10113000315 is an apocalyptic number.

10113000315 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

10113000315 is a deficient number, since it is larger than the sum of its proper divisors (7974148485).

10113000315 is a wasteful number, since it uses less digits than its factorization.

10113000315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 94528 (or 94517 counting only the distinct ones).

The product of its (nonzero) digits is 45, while the sum is 15.

Adding to 10113000315 its reverse (51300031101), we get a palindrome (61413031416).

The spelling of 10113000315 in words is "ten billion, one hundred thirteen million, three hundred fifteen", and thus it is an aban number.