1011300121 has 16 divisors (see below), whose sum is σ = 1105259904. Its totient is φ = 919747584.

The previous prime is 1011300119. The next prime is 1011300163. The reversal of 1011300121 is 1210031101.

It is a cyclic number.

It is not a de Polignac number, because 1011300121 - 2¹ = 1011300119 is a prime.

It is a super-2 number, since 2×1011300121² = 2045455869469229282, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1011300098 and 1011300107.

It is not an unprimeable number, because it can be changed into a prime (1011300221) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 266580 + ... + 270346.

It is an arithmetic number, because the mean of its divisors is an integer number (69078744).

Almost surely, 2^1011300121 is an apocalyptic number.

It is an amenable number.

1011300121 is a deficient number, since it is larger than the sum of its proper divisors (93959783).

1011300121 is a wasteful number, since it uses less digits than its factorization.

1011300121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4080.

The product of its (nonzero) digits is 6, while the sum is 10.

The square root of 1011300121 is about 31800.9452846924. The cubic root of 1011300121 is about 1003.7526073235.

Adding to 1011300121 its reverse (1210031101), we get a palindrome (2221331222).

The spelling of 1011300121 in words is "one billion, eleven million, three hundred thousand, one hundred twenty-one".