10113001211301 has 4 divisors (see below), whose sum is σ = 13484001615072. Its totient is φ = 6742000807532.

The previous prime is 10113001211279. The next prime is 10113001211303. The reversal of 10113001211301 is 10311210031101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10113001211301 - 2¹¹ = 10113001209253 is a prime.

It is a super-2 number, since 2×10113001211301² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10113001211303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1685500201881 + ... + 1685500201886.

It is an arithmetic number, because the mean of its divisors is an integer number (3371000403768).

Almost surely, 2^{10113001211301} is an apocalyptic number.

It is an amenable number.

10113001211301 is a deficient number, since it is larger than the sum of its proper divisors (3371000403771).

10113001211301 is an equidigital number, since it uses as much as digits as its factorization.

10113001211301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3371000403770.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 10113001211301 its reverse (10311210031101), we get a palindrome (20424211242402).

The spelling of 10113001211301 in words is "ten trillion, one hundred thirteen billion, one million, two hundred eleven thousand, three hundred one".