1011300213133 has 16 divisors (see below), whose sum is σ = 1223886827520. Its totient is φ = 816288767856.

The previous prime is 1011300213107. The next prime is 1011300213167. The reversal of 1011300213133 is 3313120031101.

1011300213133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011300213133 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (19).

It is a self number, because there is not a number n which added to its sum of digits gives 1011300213133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011300213233) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 22743541 + ... + 22787962.

It is an arithmetic number, because the mean of its divisors is an integer number (76492926720).

Almost surely, 2^{1011300213133} is an apocalyptic number.

It is an amenable number.

1011300213133 is a deficient number, since it is larger than the sum of its proper divisors (212586614387).

1011300213133 is a wasteful number, since it uses less digits than its factorization.

1011300213133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45531696.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1011300213133 its reverse (3313120031101), we get a palindrome (4324420244234).

The spelling of 1011300213133 in words is "one trillion, eleven billion, three hundred million, two hundred thirteen thousand, one hundred thirty-three".