101130113 has 4 divisors (see below), whose sum is σ = 115577280. Its totient is φ = 86682948.

The previous prime is 101130101. The next prime is 101130119. The reversal of 101130113 is 311031101.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 101130113 - 2⁶ = 101130049 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101130094 and 101130103.

It is not an unprimeable number, because it can be changed into a prime (101130119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7223573 + ... + 7223586.

It is an arithmetic number, because the mean of its divisors is an integer number (28894320).

Almost surely, 2^101130113 is an apocalyptic number.

It is an amenable number.

101130113 is a deficient number, since it is larger than the sum of its proper divisors (14447167).

101130113 is an equidigital number, since it uses as much as digits as its factorization.

101130113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14447166.

The product of its (nonzero) digits is 9, while the sum is 11.

The square root of 101130113 is about 10056.3469013355. The cubic root of 101130113 is about 465.9008443332.

Adding to 101130113 its reverse (311031101), we get a palindrome (412161214).

The spelling of 101130113 in words is "one hundred one million, one hundred thirty thousand, one hundred thirteen".