101130121111 has 4 divisors (see below), whose sum is σ = 101131877224. Its totient is φ = 101128365000.

The previous prime is 101130121087. The next prime is 101130121117. The reversal of 101130121111 is 111121031101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111121031101 = 463 ⋅240002227.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101130121111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101130121091 and 101130121100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101130121117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 788640 + ... + 907861.

It is an arithmetic number, because the mean of its divisors is an integer number (25282969306).

Almost surely, 2^101130121111 is an apocalyptic number.

101130121111 is a deficient number, since it is larger than the sum of its proper divisors (1756113).

101130121111 is an equidigital number, since it uses as much as digits as its factorization.

101130121111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1756112.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 101130121111 its reverse (111121031101), we get a palindrome (212251152212).

The spelling of 101130121111 in words is "one hundred one billion, one hundred thirty million, one hundred twenty-one thousand, one hundred eleven".