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1011302210114 = 2772235872151
BaseRepresentation
bin11101011011101100100…
…11110001101001000010
310120200100101112012001122
432231312103301221002
5113032121331210424
62052330312032242
7133031003644640
oct16556623615102
93520311465048
101011302210114
1135a988807709
12143bb7092682
13744999b5c31
1436d39504190
151b48daee45e
hexeb764f1a42

1011302210114 has 8 divisors (see below), whose sum is σ = 1733660931648. Its totient is φ = 433415232900.

The previous prime is 1011302210101. The next prime is 1011302210131. The reversal of 1011302210114 is 4110122031101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×10113022101142 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1011302210092 and 1011302210101.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36117936062 + ... + 36117936089.

It is an arithmetic number, because the mean of its divisors is an integer number (216707616456).

Almost surely, 21011302210114 is an apocalyptic number.

1011302210114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

1011302210114 is a deficient number, since it is larger than the sum of its proper divisors (722358721534).

1011302210114 is an equidigital number, since it uses as much as digits as its factorization.

1011302210114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72235872160.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1011302210114 its reverse (4110122031101), we get a palindrome (5121424241215).

The spelling of 1011302210114 in words is "one trillion, eleven billion, three hundred two million, two hundred ten thousand, one hundred fourteen".

Divisors: 1 2 7 14 72235872151 144471744302 505651105057 1011302210114