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10113111231 = 323831414619
BaseRepresentation
bin10010110101100100…
…11101010010111111
3222002210121021120020
421122302131102333
5131202424024411
64351303023223
7505420012206
oct113262352277
928083537506
1010113111231
11431a651173
121b62a3ab13
13c522719b2
146bd1a823d
153e2ca2606
hex25ac9d4bf

10113111231 has 8 divisors (see below), whose sum is σ = 13489816320. Its totient is φ = 6739240152.

The previous prime is 10113111223. The next prime is 10113111259. The reversal of 10113111231 is 13211131101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10113111231 - 23 = 10113111223 is a prime.

It is a super-2 number, since 2×101131112312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10113111231.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10113111271) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 700161 + ... + 714458.

It is an arithmetic number, because the mean of its divisors is an integer number (1686227040).

Almost surely, 210113111231 is an apocalyptic number.

10113111231 is a deficient number, since it is larger than the sum of its proper divisors (3376705089).

10113111231 is a wasteful number, since it uses less digits than its factorization.

10113111231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1417005.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 10113111231 its reverse (13211131101), we get a palindrome (23324242332).

The spelling of 10113111231 in words is "ten billion, one hundred thirteen million, one hundred eleven thousand, two hundred thirty-one".

Divisors: 1 3 2383 7149 1414619 4243857 3371037077 10113111231