10113112113301 has 4 divisors (see below), whose sum is σ = 10113122034400. Its totient is φ = 10113102192204.

The previous prime is 10113112113283. The next prime is 10113112113319. The reversal of 10113112113301 is 10331121131101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is an interprime number because it is at equal distance from previous prime (10113112113283) and next prime (10113112113319).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10113112113301 is a prime.

It is a super-2 number, since 2×10113112113301² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10113112113101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3230361 + ... + 5537278.

It is an arithmetic number, because the mean of its divisors is an integer number (2528280508600).

Almost surely, 2^{10113112113301} is an apocalyptic number.

It is an amenable number.

10113112113301 is a deficient number, since it is larger than the sum of its proper divisors (9921099).

10113112113301 is an equidigital number, since it uses as much as digits as its factorization.

10113112113301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9921098.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 10113112113301 its reverse (10331121131101), we get a palindrome (20444233244402).

The spelling of 10113112113301 in words is "ten trillion, one hundred thirteen billion, one hundred twelve million, one hundred thirteen thousand, three hundred one".