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10113112333113 = 33371037444371
BaseRepresentation
bin1001001100101010010001…
…1101111101101100111001
31022210210201012001010121020
42103022210131331230321
52311143123224124423
633301522154533053
72062435231330236
oct223124435755471
938723635033536
1010113112333113
113249a4629a059
121173ba4a37189
1358487c3aac4a
1426d6977da78d
151280ea3bd4e3
hex932a477db39

10113112333113 has 4 divisors (see below), whose sum is σ = 13484149777488. Its totient is φ = 6742074888740.

The previous prime is 10113112333109. The next prime is 10113112333139. The reversal of 10113112333113 is 31133321131101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10113112333113 - 22 = 10113112333109 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (10113112333213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1685518722183 + ... + 1685518722188.

It is an arithmetic number, because the mean of its divisors is an integer number (3371037444372).

Almost surely, 210113112333113 is an apocalyptic number.

It is an amenable number.

10113112333113 is a deficient number, since it is larger than the sum of its proper divisors (3371037444375).

10113112333113 is an equidigital number, since it uses as much as digits as its factorization.

10113112333113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3371037444374.

The product of its (nonzero) digits is 486, while the sum is 24.

Adding to 10113112333113 its reverse (31133321131101), we get a palindrome (41246433464214).

The spelling of 10113112333113 in words is "ten trillion, one hundred thirteen billion, one hundred twelve million, three hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 3 3371037444371 10113112333113