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101131321303 = 245171412493
BaseRepresentation
bin101111000101111100…
…1010111111111010111
3100200001000102102022201
41132023321113333113
53124104104240203
6114243055105331
710210062022225
oct1361371277727
9320030372281
10101131321303
1139986aa3591
1217724812247
1396c900892c
144c753d3b15
15296d70ae1d
hex178be57fd7

101131321303 has 4 divisors (see below), whose sum is σ = 101131978968. Its totient is φ = 101130663640.

The previous prime is 101131321279. The next prime is 101131321307. The reversal of 101131321303 is 303123131101.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101131321303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101131321307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38925 + ... + 451417.

It is an arithmetic number, because the mean of its divisors is an integer number (25282994742).

Almost surely, 2101131321303 is an apocalyptic number.

101131321303 is a deficient number, since it is larger than the sum of its proper divisors (657665).

101131321303 is an equidigital number, since it uses as much as digits as its factorization.

101131321303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 657664.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 101131321303 its reverse (303123131101), we get a palindrome (404254452404).

The spelling of 101131321303 in words is "one hundred one billion, one hundred thirty-one million, three hundred twenty-one thousand, three hundred three".

Divisors: 1 245171 412493 101131321303