Base | Representation |
---|---|
bin | 1001001100101010010110… |
… | …1101100100111001011001 |
3 | 1022210210202122022102202020 |
4 | 2103022211231210321121 |
5 | 2311143144044444113 |
6 | 33301524222125053 |
7 | 2062435603611420 |
oct | 223124555447131 |
9 | 38723678272666 |
10 | 10113133203033 |
11 | 3249a57053a23 |
12 | 1173baba20789 |
13 | 584883807303 |
14 | 26d69a4b02b7 |
15 | 1280ec142023 |
hex | 932a5b64e59 |
10113133203033 has 16 divisors (see below), whose sum is σ = 15410729342976. Its totient is φ = 5778843014160.
The previous prime is 10113133203011. The next prime is 10113133203101. The reversal of 10113133203033 is 33030233131101.
10113133203033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 10113133203033 - 210 = 10113133202009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10113133202994 and 10113133203012.
It is not an unprimeable number, because it can be changed into a prime (10113133201033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2371491 + ... + 5084312.
It is an arithmetic number, because the mean of its divisors is an integer number (963170583936).
Almost surely, 210113133203033 is an apocalyptic number.
It is an amenable number.
10113133203033 is a deficient number, since it is larger than the sum of its proper divisors (5297596139943).
10113133203033 is an equidigital number, since it uses as much as digits as its factorization.
10113133203033 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7520404.
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 10113133203033 its reverse (33030233131101), we get a palindrome (43143366334134).
The spelling of 10113133203033 in words is "ten trillion, one hundred thirteen billion, one hundred thirty-three million, two hundred three thousand, thirty-three".
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