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101132025 = 3521348427
BaseRepresentation
bin1100000011100…
…10011011111001
321001022001001120
412001302123321
5201342211100
614011335453
72335415361
oct601623371
9231261046
10101132025
11520a4a95
1229a51589
1317c4bb47
14d6079a1
158d2a0a0
hex60726f9

101132025 has 12 divisors (see below), whose sum is σ = 167205072. Its totient is φ = 53937040.

The previous prime is 101131993. The next prime is 101132033. The reversal of 101132025 is 520231101.

It is not a de Polignac number, because 101132025 - 25 = 101131993 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a junction number, because it is equal to n+sod(n) for n = 101131995 and 101132013.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 674139 + ... + 674288.

It is an arithmetic number, because the mean of its divisors is an integer number (13933756).

Almost surely, 2101132025 is an apocalyptic number.

101132025 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

101132025 is a deficient number, since it is larger than the sum of its proper divisors (66073047).

101132025 is a wasteful number, since it uses less digits than its factorization.

101132025 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1348440 (or 1348435 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 101132025 is about 10056.4419652281. The cubic root of 101132025 is about 465.9037804741.

Adding to 101132025 its reverse (520231101), we get a palindrome (621363126).

The spelling of 101132025 in words is "one hundred one million, one hundred thirty-two thousand, twenty-five".

Divisors: 1 3 5 15 25 75 1348427 4045281 6742135 20226405 33710675 101132025