101132100301 has 4 divisors (see below), whose sum is σ = 102517471612. Its totient is φ = 99746728992.

The previous prime is 101132100283. The next prime is 101132100319. The reversal of 101132100301 is 103001231101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 103001231101 = 733 ⋅140520097.

It is an interprime number because it is at equal distance from previous prime (101132100283) and next prime (101132100319).

It can be written as a sum of positive squares in 2 ways, for example, as 74774902500 + 26357197801 = 273450^2 + 162349^2 .

It is a cyclic number.

It is not a de Polignac number, because 101132100301 - 2²⁵ = 101098545869 is a prime.

It is a super-2 number, since 2×101132100301² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101132100101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 692685546 + ... + 692685691.

It is an arithmetic number, because the mean of its divisors is an integer number (25629367903).

Almost surely, 2^101132100301 is an apocalyptic number.

It is an amenable number.

101132100301 is a deficient number, since it is larger than the sum of its proper divisors (1385371311).

101132100301 is an equidigital number, since it uses as much as digits as its factorization.

101132100301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1385371310.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 101132100301 its reverse (103001231101), we get a palindrome (204133331402).

The spelling of 101132100301 in words is "one hundred one billion, one hundred thirty-two million, one hundred thousand, three hundred one".