1011323101013 has 4 divisors (see below), whose sum is σ = 1011593584320. Its totient is φ = 1011052617708.

The previous prime is 1011323100943. The next prime is 1011323101037. The reversal of 1011323101013 is 3101013231101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011323101013 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1011323100982 and 1011323101000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1011323101093) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135236045 + ... + 135243522.

It is an arithmetic number, because the mean of its divisors is an integer number (252898396080).

Almost surely, 2^{1011323101013} is an apocalyptic number.

It is an amenable number.

1011323101013 is a deficient number, since it is larger than the sum of its proper divisors (270483307).

1011323101013 is an equidigital number, since it uses as much as digits as its factorization.

1011323101013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 270483306.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1011323101013 its reverse (3101013231101), we get a palindrome (4112336332114).

The spelling of 1011323101013 in words is "one trillion, eleven billion, three hundred twenty-three million, one hundred one thousand, thirteen".