101132421231 has 4 divisors (see below), whose sum is σ = 134843228312. Its totient is φ = 67421614152.

The previous prime is 101132421217. The next prime is 101132421233. The reversal of 101132421231 is 132124231101.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 101132421231 - 2⁵ = 101132421199 is a prime.

It is a super-2 number, since 2×101132421231² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101132421198 and 101132421207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101132421233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16855403536 + ... + 16855403541.

It is an arithmetic number, because the mean of its divisors is an integer number (33710807078).

Almost surely, 2^101132421231 is an apocalyptic number.

101132421231 is a deficient number, since it is larger than the sum of its proper divisors (33710807081).

101132421231 is an equidigital number, since it uses as much as digits as its factorization.

101132421231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33710807080.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 101132421231 its reverse (132124231101), we get a palindrome (233256652332).

The spelling of 101132421231 in words is "one hundred one billion, one hundred thirty-two million, four hundred twenty-one thousand, two hundred thirty-one".