101133010111 has 4 divisors (see below), whose sum is σ = 115580582992. Its totient is φ = 86685437232.

The previous prime is 101133010079. The next prime is 101133010117. The reversal of 101133010111 is 111010331101.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111010331101 = 43 ⋅2581635607.

It is a cyclic number.

It is not a de Polignac number, because 101133010111 - 2⁵ = 101133010079 is a prime.

It is a super-2 number, since 2×101133010111² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101133010091 and 101133010100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (101133010117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7223786430 + ... + 7223786443.

It is an arithmetic number, because the mean of its divisors is an integer number (28895145748).

Almost surely, 2^101133010111 is an apocalyptic number.

101133010111 is a deficient number, since it is larger than the sum of its proper divisors (14447572881).

101133010111 is an equidigital number, since it uses as much as digits as its factorization.

101133010111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14447572880.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 101133010111 its reverse (111010331101), we get a palindrome (212143341212).

The spelling of 101133010111 in words is "one hundred one billion, one hundred thirty-three million, ten thousand, one hundred eleven".