10113311213 has 4 divisors (see below), whose sum is σ = 10255752288. Its totient is φ = 9970870140.

The previous prime is 10113311191. The next prime is 10113311231. The reversal of 10113311213 is 31211331101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31211331101 = 17 ⋅1835960653.

It is a cyclic number.

It is not a de Polignac number, because 10113311213 - 2⁶ = 10113311149 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10113311191 and 10113311200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10113311293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71220431 + ... + 71220572.

It is an arithmetic number, because the mean of its divisors is an integer number (2563938072).

Almost surely, 2^10113311213 is an apocalyptic number.

It is an amenable number.

10113311213 is a deficient number, since it is larger than the sum of its proper divisors (142441075).

10113311213 is an equidigital number, since it uses as much as digits as its factorization.

10113311213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 142441074.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 10113311213 its reverse (31211331101), we get a palindrome (41324642314).

The spelling of 10113311213 in words is "ten billion, one hundred thirteen million, three hundred eleven thousand, two hundred thirteen".